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We can represent ln(1+x_) with a power series by representing its derivative as a power series and then integrating that series. You have to admit this is pretty neat. Created by Sal Khan. Practice this lesson yourself on KhanAcademy.org right now: https://www.khanacademy.org/math/ap-calculus-bc/bc-series/bc-power-series/e/creating-power-series-from-geometric-series-using-differentiation-and-integration?utm_source=YT&utm_medium=Desc&utm_campaign=APCalculusBC Watch the next lesson: https://www.khanacademy.org/math/ap-calculus-bc/bc-series/bc-power-series/v/finding-function-from-series-by-integrating?utm_source=YT&utm_medium=Desc&utm_campaign=APCalculusBC Missed the previous lesson? https://www.khanacademy.org/math/ap-calculus-bc/bc-series/bc-power-series/v/finding-power-series-through-integration?utm_source=YT&utm_medium=Desc&utm_campaign=APCalculusBC AP Calculus BC on Khan Academy: Learn AP Calculus BC - everything from AP Calculus AB plus a few extra goodies, such as Taylor serie
We can represent ln(1+x_) with a power series by representing its derivative as a power series and then integrating that series. You have to admit this is pretty neat. Created by Sal Khan. Practice this lesson yourself on KhanAcademy.org right now: https://www.khanacademy.org/math/ap-calculus-bc/bc-series/bc-power-series/e/creating-power-series-from-geometric-series-using-differentiation-and-integration?utm_source=YT&utm_medium=Desc&utm_campaign=APCalculusBC Watch the next lesson: https://www.khanacademy.org/math/ap-calculus-bc/bc-series/bc-power-series/v/finding-function-from-series-by-integrating?utm_source=YT&utm_medium=Desc&utm_campaign=APCalculusBC Missed the previous lesson? https://www.khanacademy.org/math/ap-calculus-bc/bc-series/bc-power-series/v/finding-power-series-through-integration?utm_source=YT&utm_medium=Desc&utm_campaign=APCalculusBC AP Calculus BC on Khan Academy: Learn AP Calculus BC - everything from AP Calculus AB plus a few extra goodies, such as Taylor serie
Courses on Khan Academy are always 100% free. Start practicing—and saving your progress—now: https://www.khanacademy.org/math/ap-calculus-bc/bc-series-new/bc-10-12/v/proof-bounding-the-error-or-remainder-of-a-taylor-polynomial-approximation The more terms we have in a Taylor polynomial approximation of a function, the closer we get to the function. But HOW close? In this video, we prove the Lagrange error bound for Taylor polynomials. Created by Sal Khan. Watch the next lesson: https://www.khanacademy.org/math/ap-calculus-bc/bc-series/bc-taylor-series/v/lagrange-error-bound-for-sine-function?utm_source=YT&utm_medium=Desc&utm_campaign=APCalculusBC Missed the previous lesson? https://www.khanacademy.org/math/ap-calculus-bc/bc-series/bc-taylor-series/v/error-or-remainder-of-a-taylor-polynomial-approximation?utm_source=YT&utm_medium=Desc&utm_campaign=APCalculusBC AP Calculus BC on Khan Academy: Learn AP Calculus BC - everything from AP Calculus AB plus a few extra goodies, such as Tay
Courses on Khan Academy are always 100% free. Start practicing—and saving your progress—now: https://www.khanacademy.org/math/ap-calculus-bc/bc-series-new/bc-10-12/v/proof-bounding-the-error-or-remainder-of-a-taylor-polynomial-approximation The more terms we have in a Taylor polynomial approximation of a function, the closer we get to the function. But HOW close? In this video, we prove the Lagrange error bound for Taylor polynomials. Created by Sal Khan. Watch the next lesson: https://www.khanacademy.org/math/ap-calculus-bc/bc-series/bc-taylor-series/v/lagrange-error-bound-for-sine-function?utm_source=YT&utm_medium=Desc&utm_campaign=APCalculusBC Missed the previous lesson? https://www.khanacademy.org/math/ap-calculus-bc/bc-series/bc-taylor-series/v/error-or-remainder-of-a-taylor-polynomial-approximation?utm_source=YT&utm_medium=Desc&utm_campaign=APCalculusBC AP Calculus BC on Khan Academy: Learn AP Calculus BC - everything from AP Calculus AB plus a few extra goodies, such as Tay
