Mukul Kashyap vs Debananda Pame | 62 Kg | All India Open BJJ Championship 2021 | NMMMAA | Full Fight

Wrestling

سال2021

ابھی دیکھیں

0

Here is the full fight from the 62 Kg Category between Mukul Kashyap (Blue) and Debananda Pame (Red) which was held at All India Open BJJ Championship 2021. The All India Open BJJ Championship was held at the Nerul Gymkhana in Navi Mumbai on 27th November 2021. The event was organized by the Navi Mumbai Mixed Martial Arts Association and was supported by Fit and Fight Club, Urban Chakki, Iron Wolf 207, Healthio, Two Brothers Organic Farms and was streamed live on the LockerRoom India YouTube Channel. LockerRoom India was the media partner for the event. The Championship saw around 100 grapplers from around the country. #BJJ #NaviMumbai #NMMMAA LockerRoom is home to the first-ever mobile app from India which is dedicated to MMA and Combat Sports news. Download the LockerRoom App for all the latest MMA news: http://onelink.to/6gkfh8 ----------------------------------------------------- You can check us out on: ------------------------------------------------------- Website: https://lockerroom.in/ All our Social Media Pages: https://linktr.ee/lockerroomindia Instagram (LockerRoom India) https://www.instagram.com/lockerroom_in Instagram (LockerRoom Boxing) https://www.instagram.com/boxinglockerroom/ Instagram (LockerRoom Fitness) https://www.instagram.com/fitnesslockerroom/ Twitter: https://twitter.com/lockerroom_in Facebook: https://www.facebook.com/lockeroom.in/ Follow us on Google News: https://news.google.com/publications/CAAqBwgKMNnsmwswnfezAw Telegram: LockerRoom India: https://t.me/lockerroomindia LockerRoom Fitness: https://t.me/lockerroomfitness LockerRoom Boxing: https://t.me/lockerroomboxing DISCLAIMER: Copyright Disclaimer under section 107 of the Copyright Act 1976, allowance is made for “fair use” for purposes such as criticism, comment, news reporting, teaching, scholarship, education, and research. Fair use is a use permitted by copyright statute that might otherwise be infringing.