In #Laws #of #Indices, a number to a negative index or exponent is expressed as a reciprocal of the number a positive common exponent. Mathematically; a⁻ⁿ = 1/aⁿ for a and n not equal to zero In this video I'm going to prove this law for you. If you find this video interesting, kindly subscribe to my channel for more exciting Maths tutorials. Subscribe link: Facebook: Instagram: Linkedin: Blog:
Ketuk kartu di bawah untuk lanjut melihat lebih banyak pilihan hiburan.
Mungkin Anda Juga Suka
Celebrating STEM: counting and multiplication
SSS 1 Mathematics
Mathematics Lessons for JAMB, WAEC, NECO, NABTEB, SS1, SS2 and SS3 students
Pry1 Math
Pry 1 Primary Mathematics
Pry 2 Primary Mathematics
SS ONE | MATHEMATICS | GRADE 10 | FIRST TERM
Year 10 Math
Algebra I | High School Math | Khan Academy
Numberblocks - How to Count to Ten | Learn to Count
Algebra II | High School Math | Khan Academy
4th Grade Learning Videos
SSS10 Math
SSS12 Math
SSS11 Math
JSS7 Math
SSS 2 Mathematics
Matholia Primary 3
JSS2 Mathematics
Matrices
SS 1 Biology
SS 1 Chemistry
SS 1 Mathematics
SS 1 Physics
Komentar
10 Komentar
Proving x⁰=1 Logically.
Proving x⁰=1 Logically.
Simple Logarithmic Equation
Simple Logarithmic Equation
Exponential Equation 3ˣ+9ˣ=27ˣ
Exponential Equation 3ˣ+9ˣ=27ˣ
Exponential Equation | e^2x + 2e^x - 15 = 0
Exponential Equation | e^2x + 2e^x - 15 = 0
Exponential Equation | x^(x•x^½)=(x•x^½)^x
Exponential Equation | x^(x•x^½)=(x•x^½)^x